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How is the volume of a sphere affected if you double the radius?
The volume of a sphere is proportional to R3 .So doubling the radius causes the volume to increase by a factor of 23 = 8 .
How do you work out the volume of a sphere with a known diameter?
The volume inside a sphere (that is, the volume of the ball) is given by the formula:-Volume = 4/3πr3where 'r' is the radius of the sphere and 'π' is the constant piThe diameter of a sphere is two times its radius, thus a sphere 8 meters in diameter has a radius of 4 meters.
What is the volume of a sphere of radius 8 cm?
Volume of a sphere = 4/3*pi*radius3 Volume = 2144.660585 cubic cm
If the radius of a sphere is doubled how does this affect the volume?
The volume is increased by a factor of 23 = 8.
What is the volume of a sphere with a radius of 8 yards?
2,144.66 cubic yards.
What is the volume of a sphere with a radius of 8 millimeters?
V = 2,144.7 cubic mm
Find the volume of a sphere with a radius of 8?
Volume of a sphere = 4/3 pi R3 = 4/3 pi 83 = 2144.66 (rounded)
What is the volume of sphere with 8m?
If 8m is its radius then the volume of the sphere is: 4/3*pi*8^3 = 2145 cubic m rounded
If a radius of a sphere is doubled what happens to the volume?
The volume is proportiuo9nal to the cube of the radius, so doubling the radiuscauses the volume to increase to (2)3= 8 times its original value.
What is the volume of a sphere with a radius of 8 mm Round the answer to the nearest whole number.?
Volume of sphere: 4/3*pi*8^3 = 2145 cubic mm to the nearest whole number
How many times greater is the volume of a sphere with a radius of 5 than a radius of 2.5?
Volumes: 523.5987756/65.44984695 = 8 times greater 53/2.53 = 8
That the height of the cone of maximum volume that can be inscribed in a sphere of radius 12cm is 16cm?
The height of the cone of maximum volume that can be inscribed in a sphere of radius 12 cm is not 16 cm; it is actually 16 cm when considering the relationship between the cone's dimensions and the sphere's radius. The cone's volume is maximized when its height is two-thirds of the sphere's radius, which means the optimal height is ( \frac{2}{3} \times 12 \text{ cm} = 8 \text{ cm} ). Thus, the statement is incorrect; the correct height for maximum volume is 8 cm, not 16 cm.
