I assume you mean 4 X 10^-17 Joules.
Energy = Planck's constant * speed of light/wavelength in meters
4 X 10^-17 Joules = (6.626 X 10^-34 J*s)(2.998 X 10^8 m/s)/wavelength
wavelength in meters = (6.626 X 10^-34)(2.998 X 10^8)/(4 X 10^-17)
= 4.9662 X 10^-9 meters
or
4.97 nanometers
4.9695 nm
(17-4)+10=23 13+10=23
a - 3 + 17 = 10 Therefore, a - 3 = -7 a = -4
8/17 ÷ 4/5 = 40/68 which can be simplfied to 10/17.
40 x 170 = 4 x 10 x 17 x 10 which equals 4 x 17 x 10 x 10 which becomes 4 x 17 x 100 = 68 x 100 = 6800 Or, you can multiply 4x17, then put two zeroes on the end.
4.9695 nm
4.8 - 5.2 nm
The wavelength is w = hc/E = .2E-24/4E-17 = 5E-9 meters.
c = wavelength X frequency, where c is the speed of light, which is 299,792,458 m/s. So you need the wavelength of the photon. Then you divide c/wavelength and the result will be the frequency.
The energy carried by a photon is given byE = hfWhere h is Planck's constant (6.626x10^-34 Joule-seconds) and f is the frequency of the photon in Hertz (Hz).We are given the wavelength of the photon in the question in nanometers (nm). First, we need to convert this to (SI) units, because our equations only work with SI units. Then, we will calculate the frequency of the photon from its wavelength. Once we know the frequency of the photon we're interested in, we simply use the equation above to find the energy carried by one of them. Then we divide 6 kJ by that amount of energy, and the quotient will be the number of photons needed to carry 6 kJ. Finally, when we know the number of photons we need, we divide by the number of photons in a mole to get the number of moles.The SI unit of length is the meter (m). 1nanometer (nm) is 10^-9 meters.660 nm = 660 *10^-9 m = 6.6*10^-7 m.Now we will calculate this photon's frequency from its wavelength. These are related by the equationc = fLwhere c is the speed of light (3*10^8 m/s), f is the frequency of the photon and L is the wavelength of the photon.c = fL(3*10^8 m/s) = f * (6.6*10^-7 m)solving for f, we havef = (3*10^8 m/s) / (6.6*10^-7 m) = 4.54*10^15 s^-1Note that the unit of seconds (s) raised to the -1power is defined as 1 Hertz (Hz).f = 4.54*10^15 HzNow we will use the top equation to solve for the energy carried by one photon having this frequency.E = hfE = (6.626*10^-34 Js) * (4.54*10^15 Hz)E = 1.369*10^-17 JThis is how much energy is carried by one photon of wavelength 660 nm (which will also have a frequency of 4.54*10^15 Hz).How many of these do we need to provide 6 kJ? This is solved by simple division. Keeping in mind that 1 kJ = 1000 J, we haveNumber of photons * Energy per photon = 6 kJNumber of photons * (1.369*10^-17 J/photon) = 6 kJNumber of photons * (1.369*10^-17 J/photon) = 6000 JNumber of photons = 6000 J / (1.369*10^-17 J/photon)Number of photons = 4.382*10^20 photonsThis is how many photons (at this frequency) are needed to provide 6 kJ. How many moles of photons is this?Number of photons / number of photons in a mole = number of molesRecall that a mole of something is defined as 6.02*10^23of it. The same way a dozen eggs is defined as 12 eggs, a mole of eggs is 6.02*10^23 eggs. Equivalently, a mole of photons is 6.02*10^23 photons. SoNumber of photons / (6.02*10^23 photons per mole) = number of moles(4.382*10^20 photons) / (6.02*10^23 photons per mole) = number of moles7.279*10^-4 moles = number of molesForgive me if my arithmetic is off, as I don't have a good calculator handy. However, I believe this is the correct method to use.
Frequency = speed/wavelength = 299,792,458/4.5 x 10-4 = 666.21 GHz . (rounded)
That is the "gamma" line of the Lyman series: 94.97 nanometers.
3/10 is greater than 4/17. 3/10 = 3/10 * 17/17 = 51/170 4/17 = 4/17 * 10/10 = 40/170 thus 3/10 > 4/17.
5.10 x 10^14 hz
wavelength=velocity/frequency (v/f). wavelength=(3x10/4x10)=30/40=.75 meters
(17-4)+10=23 13+10=23
The end value of "n" is 2.