First of all we need to define the cross sectional area of the rod. If it is a cylinder rod we would use pi * r^2, Do this metrically to make things easy (metres). next we times that by a ft (in metric it is 30cm) so do: cross sectional area * 0.3m. this is the volume of the steel per foot. now find out the weight per cubic cm (density) and multiply them. To find mass of a material you need to weigh it, or times its relative Atomic Mass by the number of moles. You'll have to find the density of your steel as you havn't specified what kind and there isn't a 'pure' steel as its an alloy.
The weight of 1 foot of steel rod would depend on the diameter of the rod.
.4017
The volume is 150.152 cm3. The density of steel varies according to the constituents but is normally between 7.75 and 8.05 grams per cm3. Using g = 9.8, this range would give a weight in the range 11.4-11.8 Newtons.
There is no way to determine weight of random dimensions. The weight of 3.5 meters of thread is going to be vastly different than 3.5 meters of steel rod.
You need the length of the rod to compute the weight. To do so, you can calculate the volume of the rod, which would be length*Pi*22 multiplied by the density of MS, which is 7.86 g/cm3, or simply 15.72(Pi)*length of the rod Mildsteel rod 40mm dia. = 9.85 kg per metre. I think that is what you asked.
The weight of 1 foot of steel rod would depend on the diameter of the rod.
.4017
16 m m steel rod weight per meter = 1.5816 m m steel rod of 12metres weights = 12 * 1.58 = 18.96 kg
weight of all steel can be calculated by multiplying unit volume with density.
10.66
=D^((D^2/162) L) D^2 = Diameter of the rod L = Length of the rod
the rod will be stronger, but will break, the cable will bend under force, but not break. the rod has more tensile and shear strength.
The unit pounds per foot is a linear weight measurement, for a rod, tube, or beam of a known diameter or cross-section. Divide the total weight in pounds by the length of the sample.Much more useful is the unit pounds per square foot(related to psi, pounds per square inch), which gives either bearing weight or pressure for a known mass when distributed over a given area.
6.320kg/m
In order to find the weight of the steel rod, we must know is mass and volume.Volume of a cylinder:Pi x r2 x lengthpi x (0.00514)2 x 1Volume = 8.3x10-5 m3Steel has a density of 7850 kg/m3Therefore the mass of the steel rod = 7850 x 8.3x10-5 = 0.652 kgWeight of rod = 0.652 x 9.81Weight of rod = 6.39 Newtons
Steel rod weight per inch.... this depends on the thickness and shape of the steel rod. The density of steel is around 500 pounds per cubit foot, so, for example: If the rod is cylindrical and has a diameter of 1/2 inch, each "inch" of the rod is a cylinder with length L=1. The volume of this cylinder is found with pi*r^2*L. Since diameter = .5in, radius = .25in. pi*.25^2*1 = about .2in^3 or 1/5 cubic inch. Now, a cubic inch is about 5.8*10^-4 cubic feet, so... 500lb/ft^3 * 5.8*10^-4 in^3/ft^3 = .28935 pounds per cubic inch. We have one fifth cubic inch, so multiply that by .2... and each inch of our rod weighs .05787 pounds, which is pretty much 3/50 pounds. Coincidentally, 3/50 of a pound is just about an ounce, so our cylindrical steel rod of diameter 1/2 inch pretty much weighs one ounce per inch!
1.58 kg