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An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. No number is both.
No. In fact, no number can be both odd and even at the same time.
As 8 is even, and 3 is odd, I think only 1 can go into both.
Both are odd they don't end in an even number (0,2,4,6,8)
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 0 is an even number.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. No number is both.
There is only one number and it is odd.
No. In fact, no number can be both odd and even at the same time.
Decimal numbers generally are not considered to be odd or even. Only integers are odd or even. So on that basis, 3.6 is not an odd number, but neither is it an even number.
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As 8 is even, and 3 is odd, I think only 1 can go into both.
No. The opposite is true: the gcf of an odd number and an even number is always odd. All the factors of an odd number are odd; or to put it another way: If a number has an even factor, the number itself must be even. Thus the only common factors between odd and even numbers must be odd.
Both are odd they don't end in an even number (0,2,4,6,8)
The only even prime number is 2, then its successor is 3
Probability zero. If both dice have the same number, then the result will be even. If both dies are odd (as in the case of 5) then the sum is even. If both dies are even, the sum is also even. The only way to get an odd sum is to have one die have an odd number and the other die have an even number. That will happen 50% of the time.The probability of both dice showing 5 is 1/36. But the two events will never happen at the same time.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 0 is an even number.
Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd. ========================== You've just read a truly impressive answer to a question slightly different from the one that was asked. The part of the question that comes after "Why if ..." is a false statement. If you multiply odd number with another number, the result is odd number ONLY if the nother number is also odd number.