odd * odd = odd answer even * even = even answer odd * even = even answer
Both odd and even numbers may have odd numbers as factors.
yes, the product of 2 odd numbers is always an odd number. Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.
Odd
Both 27 and 37 are odd numbers. Neither is an even number.
No. In fact, no number can be both odd and even at the same time.
Both are odd they don't end in an even number (0,2,4,6,8)
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 0 is an even number.
Any number evenly divisible by an even number is also even. A number evenly divisible by an odd number (such as 5) could be either even or odd.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. No number is both.
There is no such number. Many people mistakenly say that 0 is both even and odd or that 0 is neither even nor odd. 0 is even by every mathematical definition of the word "even" and is not odd by every mathematical definition of the word "odd."
You can't see it, as both even and odd numbers are infinite
odd * odd = odd answer even * even = even answer odd * even = even answer
numbers which are divisible by both an even number and odd number greater than 1: 6, 10, 12, 14, 18, ...
Both odd and even numbers may have odd numbers as factors.
yes, the product of 2 odd numbers is always an odd number. Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.
No. Both are odd numbers.