y=mx + c
c is where the line goes thrugh the y axis
find gradient (m) by rise over run. for example if the line goes up 2 every time it goes across 1 the gradient is 2/1 which is just 2. get it?
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
Assuming that the point is located at (1,1) then the equation is: y = -3x + 4 We know this by multiplying the slope by the x of the point given, and finding the difference between this value, and the y value of the point. 1 - (-3) is 4, hence the +4 in our equation.
If the slope m is given at a point (xo, yo) of a line, then the equation of the line is given by: y - yo = m(x - xo)
Use point-slope formula
wew
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
plug in the slope(m) and coordinates (x,y) into the slope-intercept formula & solve for b.slope-intercept formula: y=mx+b
Assuming that the point is located at (1,1) then the equation is: y = -3x + 4 We know this by multiplying the slope by the x of the point given, and finding the difference between this value, and the y value of the point. 1 - (-3) is 4, hence the +4 in our equation.
If the slope m is given at a point (xo, yo) of a line, then the equation of the line is given by: y - yo = m(x - xo)
Substitute the coordinates of the point into the equation of the line. If the equation is still valid then the point is on the line; if not then it is not.
You must first write an equation for the line through the point perpendicular to the line. Then, find the intersection between the two lines. Lastly, use this point and the distance formula to find the length of the perpendicular segment connecting the given point and the original line. That will lead to the following formula, d = |AX1+BY1- C|/(sqrt(A2+B2)), Where A, B and C represent the coefficients of the given line in standard form and (X1,Y1) is the given point.
Given point: (6, 7) Equation: 3x+y = 8 Parallel equation: 3x+y = 25