Width is 16.
The perimeter of a rectangle = 2 x (length + width) = 2 x (12 + 8) = 2 x 20 = 40 inches
The diagonal is 20.
the answer to number 20 is B...12
If a rectangle is 40 inches. the rectangle is 12 inches long then: 2 * 12 + 2 * width = 40 2 * width = 40 - 2*12 = 40 - 24 = 16 width = 16 / 2 = 8 So the width of the rectangle is 8.
has an area of 240 square inches
First find the dimensions of the rectangle. Let the length be x+4 and the width be x: 2(x+4+x) = 20 2x+8+2x = 20 4x = 20-8 4x = 12 => x = 3 Therefore: length = 7cm and the width = 3cm Area = length*width => 21cm2
If the length of a rectangle is 12 and the width of the rectangle is 16, by the Pythagorean theorem we know that one diagonal is 20 units long. You can draw two diagonals within a rectangle, so the length of both diagonals together is 20+20 = 40 units.
12*2+20*2 = 64 mm
The perimeter of a rectangle is 2length +2 width. the width is x the length is x+4. Plug into the equation 2(x)+2 (x+4)=20 2x+2x+8=20 4x=12 x=3 The width is 3 the length is 7 (3+4) Area is length times width. 3(7)= 21. the area is 21 centimeters
The area of the rectangle is 72 square feet
length + width = 20/2 = 10 length = 7cm, width = 3cm