First find the dimensions of the rectangle. Let the length be x+4 and the width be x:
2(x+4+x) = 20
2x+8+2x = 20
4x = 20-8
4x = 12 => x = 3
Therefore: length = 7cm and the width = 3cm
Area = length*width => 21cm2
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
the width equals 14 cm. and the length equals 31 cm.
you need length and width length multiply width = area length + length + width + width = perimeter
Length + length + width + width = perimeter. Length + width x 2 = perimeter
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
The perimeter of a rectangle whose length is 5cm wit a width of 6cm is 22cm
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
the width equals 14 cm. and the length equals 31 cm.
21cm3
The perimeter of a rectangle is found by the following formula: (Length x 2) + (Width x 2) or Length + Length + Width + Width.
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
i don't know what length of rectangle is 7 cm longer than the width the perimeter of the rectangle is 46 cm .what is the length of the of the rectangle ?