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A = 3x2 + 9xy + 6y2

l = 3x + 6y

A = l×w

∴ w = A/l

∴ w = (3x2 + 9xy + 6y2) / (3x + 6y)

∴ w = x + 1

Q: What is the width of a rectangle if the area is 3x2 plus 9xy plus 6y2 and the length is 3x plus 6y?

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Area of a rectangle is length x width. It isn't clear what the width is in this case - or how you could solve for it.

a rectangle

6x2+19x+10 = (2x+5)(3x+2) Length = 2x+5 Width = 3x+2

Perimeter: (2*L)+(2*W) [length times two plus width times two] Area: L*W [length times width]

For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.

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The area is the length times the width. The perimeter is two times the length plus two times the width.

The area is the length times the width. The perimeter is two times the length plus two times the width.

56

The area is the length times the width. The perimeter is two times the length plus two times the width.

Perimeter: Add the length of the four sides. Area: Multiply length x width.

Area of a rectangle is length x width. It isn't clear what the width is in this case - or how you could solve for it.

a rectangle

2 times length plus 2 times width = perimeterhalf the perimeter of a rectangle

6x2+19x+10 = (2x+5)(3x+2) Length = 2x+5 Width = 3x+2

Perimeter: (2*L)+(2*W) [length times two plus width times two] Area: L*W [length times width]

For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.

The formula for finding the area of a rectangle is A = LW. You can find the length by dividing the area by the width: A = LW x² + 50x = L * x (x² + 50x)/x = L X + 50 = L