A = 3x2 + 9xy + 6y2
l = 3x + 6y
A = l×w
∴ w = A/l
∴ w = (3x2 + 9xy + 6y2) / (3x + 6y)
∴ w = x + 1
a rectangle
Area of a rectangle is length x width. It isn't clear what the width is in this case - or how you could solve for it.
6x2+19x+10 = (2x+5)(3x+2) Length = 2x+5 Width = 3x+2
Perimeter: (2*L)+(2*W) [length times two plus width times two] Area: L*W [length times width]
For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.
The area is the length times the width. The perimeter is two times the length plus two times the width.
The area is the length times the width. The perimeter is two times the length plus two times the width.
56
The area is the length times the width. The perimeter is two times the length plus two times the width.
a rectangle
Perimeter: Add the length of the four sides. Area: Multiply length x width.
Area of a rectangle is length x width. It isn't clear what the width is in this case - or how you could solve for it.
2 times length plus 2 times width = perimeterhalf the perimeter of a rectangle
6x2+19x+10 = (2x+5)(3x+2) Length = 2x+5 Width = 3x+2
Perimeter: (2*L)+(2*W) [length times two plus width times two] Area: L*W [length times width]
For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.
The formula for finding the area of a rectangle is A = LW. You can find the length by dividing the area by the width: A = LW x² + 50x = L * x (x² + 50x)/x = L X + 50 = L