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3x+y=13

x+6y=-7

Multiply the second equation by -3 to cancel out the x's:

3x+y=13

-3x-18y=21

Find the sum of the y's and the numbers:

-17y=34

Divide by -17 on both sides:

y=-2

Plug the y back into one of the equations to find x:

3x -2=13

Add 2 to both sides:

3x=15

Divde each side by 3:

x=5

Plug both numbers back into the equations:

3∙5 -2=13

15-2=13

13=13

5+6∙-2=-7

5+-12=-7

-7=-7

Therefore x =5

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Q: What is the x-coordinate of the solution to the system of linear equations 3x plus y equals 13 and x plus 6y equals -7?
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