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-2
If: (2x+10)(3x-15) = 0 => x^2-25 = 0 => (x-5)(x+5) = 0 So: x = 5 or x = -5
3x - y = 0 5y = 15 5y = 15 Divide by '5' on both sides Hence y = 3 Substitute for 'y' in the first equation./ 3x - 3 = 0 3x = 3 Divide both sides by ;3; x = 1 So in ( x,y) form the answer is ( 1,3).
15
negative 15
Do you mean "what is the value of x when 3x - 2x = 15?" in that case, the value of x is 15
Given LBRW and = 15 and = 3x - 9, what is the value of x? 8
If you mean: x^2+15-3x then its value is 19 when x equals 4
1) 3x-17=0 3x=17 x=17/3 2) 3x-25=0 3x=25 x=25/3
-3x + 5y = -15At the x-intercept, y=0:-3x = -15 . . . . . x = 5At the y-intercept, x=0:5y = -15 . . . . . y = -3
-2
If: (2x+10)(3x-15) = 0 => x^2-25 = 0 => (x-5)(x+5) = 0 So: x = 5 or x = -5
15
3x - y = 0 5y = 15 5y = 15 Divide by '5' on both sides Hence y = 3 Substitute for 'y' in the first equation./ 3x - 3 = 0 3x = 3 Divide both sides by ;3; x = 1 So in ( x,y) form the answer is ( 1,3).
negative 15
Assuming the equation is 3x + y = 15, then the x-intercept is (5, 0) and the y-intercept is (0, 15).
The absolute value of -15, written as |-15| = 15.