Assuming the equation is 3x + y = 15, then
the x-intercept is (5, 0) and the y-intercept is (0, 15).
3x^2 -14x +15 = (3x-5)(x-3)
Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
x intercept = (5, 0) y intercept = (0, -2)
(a) y = -3x + 1
3x + y = 12The x intercept occurs when y = 0. Then, 3x + 0 = 12 : 3x = 12 : x = 4The y intercept occurs when x = 0. Then, (3 x 0) + y = 12 : y = 12.
X intercept: -5 Y intercept: +3
x intercept = 5 y intercept = 15
3x-9y-27
They are: 6 and -3
-3x + 5y = -15At the x-intercept, y=0:-3x = -15 . . . . . x = 5At the y-intercept, x=0:5y = -15 . . . . . y = -3
3x - 5 + 3x = 1x + 15 3x + 3x -1x = 15 + 5 5x = 20 5x/5 = 20/5 x = 4
x+5 = 3x+15 x-3x = 15-5 -2x = 10 x = -5
no
If 15 + 3x = 42, then x = 9
Factorising, we have, 9x2+ 30x + 25 = (3x + 5)2;thus, when y = 0, x = -1⅔. This tells us that the sole x-intercept of this function is at the vertex, (0, 1⅔).
3x+12x = 15 15x = 15 x = 1
The intercept of -3x + 5y - 2z = 60 are (-20, 0, 0), (0, 12, 0) and (0, 0, -30).