If you mean: x+2y = -6 then y = -1/2x-3 whereas -1/2 is the slope and -3 is the y intercept
If you mean 9x-2y = 6 then it is a straight line equation that can be expressed as y = 4.5x-3 whereas 4.5 is the slope and -3 is the y intercept.
It depends very much on what the question is!
I assume you mean......3X - 2Y = 6- 2Y = - 3X + 6Y = (3/2)X - 3=============now, zero out variables in turnY = (3/2)0 - 3Y = - 3===Y intercept = (0, - 3)X intercept = (2, 0)
Unfortunately not all of the notation made it through. If neither of the variables is raised to some power, say x2 or y3, then the expression or equation appears to be linear.
If you mean: 3x+2y = 6 and -4x+5y = 15 then it works out as x = 0 and y = 3
If you mean 9x-2y = 6 then it is a straight line equation that can be expressed as y = 4.5x-3 whereas 4.5 is the slope and -3 is the y intercept.
2y6 is an expression not an equation. This is an equation: 2y = 6 To solve that equation you divide each side of the equation by 2: 2y/2= 6/2 y = 3
x + 2y6 cannot be simplified, nor evaluated, nor solved.
It depends very much on what the question is!
I assume you mean......3X - 2Y = 6- 2Y = - 3X + 6Y = (3/2)X - 3=============now, zero out variables in turnY = (3/2)0 - 3Y = - 3===Y intercept = (0, - 3)X intercept = (2, 0)
Unfortunately not all of the notation made it through. If neither of the variables is raised to some power, say x2 or y3, then the expression or equation appears to be linear.
Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals". My guess is that these are straight lines and therefore there is just one solution.
2(x - y)(x + y)(x2 - xy + y2)(x2 + xy + y2)
If you mean: 3x+2y = 6 and -4x+5y = 15 then it works out as x = 0 and y = 3
If the slopes of the lines are negative reciprocals, then the lines are perpendicular.2x - 5y = -3 subtract 2x to both sides-5y = -2x - 3 divide both sides by -5y = (2/5)x +3/55x + 2y = 6 subtract 5x to both sides2y = -5x + 6 divide both sides by 2y = (-5/2)x + 3Yes, the lines are perpendicular.