They are the complex conjugate numbers +/- 3*sqrt(2)*i where i is the imaginary square root of -1.
In the equation x + 9 = 6, x is negative.
It has no solutions because the discriminant of the quadratic equation is less than zero.
No because the discriminant is less than zero.
It has no roots because the discriminant of the given quadratic equation is less than zero.
No. Although this an equation of a straight line and y increases when x increases, a directly proportional equation has y/x = constant. So if b is zero it is in direct proportion, but not if b is non zero
Zero.
In the equation x + 9 = 6, x is negative.
The discriminant is -167.
There are no real solutions because the discriminant of the quadratic equation is less than zero.
This quadratic equation has no real roots because its discriminant is less than zero.
It can't be factored because its discriminant is less than zero.
No because the discriminant is less than zero.
It has no solutions because the discriminant of the quadratic equation is less than zero.
It has no roots because the discriminant of the given quadratic equation is less than zero.
are you sure from this equation ? x^2 + 9x + 11 ____________ = zero x + 7 or there is no zero ?? please be sure from the x^2 + 9x + 11 ???
No. Although this an equation of a straight line and y increases when x increases, a directly proportional equation has y/x = constant. So if b is zero it is in direct proportion, but not if b is non zero
If it was expressed as a quadratic equation it would have no roots because the discriminant is less than zero