It can't be factored because its discriminant is less than zero.
(5x - 4)(2x + 3)
10x2 - 64 = 36 + 6x2; whence, 4x2 - 100 = 0, x2 = 25, and x = ±5.
10x2 + 101x + 10 = (10x + 1)(x + 10)
If that's - 94x, the answer is 2(3x - 10)(x2 + 5x + 1)
4x3+10x2+2x+5= (2x+5)(2x2+1)
If: 10x2-64 = 36+6x2 Then: 4x2-100 = 0 And: (2x-10)(2x+10) = 0 So: x = 5 or x = -5
The answer is 21
This polynomial doesn't factor. The only thing you can do is take out parts of some terms, e.g. 2(2x3 + 10x2 + x) - 3.
Given: x4 + 3x3 - 10x2 = 0 You can start by dividing both sides of the equation by x2: x2 + 3x - 10 = 0 Then factor out the left side of the equation into simpler terms: (x + 5)(x - 2) = 0 For the result to be 0, either of the terms in brackets on the left must equal 0, so that means there are two answers: x = -5, x = 2
10*2+3*4 = 32 = 2^5 Not really sure what you are looking for? I doubt you would ever need to factorise this. It might help if you gave the specific form you would like it in.
Multiply all terms by 10 it then becomes 10x2+13x+4 = (5x+4)(2x+1) when factored.
10x2 - 20xz + 15xy = 5x (2x - 4z + 3y)