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Q: Can you please factor this equation 10x2 plus 7x plus 12?

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That doesn't factor neatly. Applying the quadratic equation, we find two real solutions: (31 plus or minus the square root of 401) divided by 20x = 2.5512492197250394x = 0.5487507802749606

(5x - 4)(2x + 3)

10x2 - 64 = 36 + 6x2; whence, 4x2 - 100 = 0, x2 = 25, and x = ±5.

(x + 3)(x + 1)(x - 3)(x -1)

10x2 + 101x + 10 = (10x + 1)(x + 10)

4x3+10x2+2x+5= (2x+5)(2x2+1)

The answer is 21

If that's - 94x, the answer is 2(3x - 10)(x2 + 5x + 1)

10x2 - 20xz + 15xy = 5x (2x - 4z + 3y)

If: 10x2-64 = 36+6x2 Then: 4x2-100 = 0 And: (2x-10)(2x+10) = 0 So: x = 5 or x = -5

This polynomial doesn't factor. The only thing you can do is take out parts of some terms, e.g. 2(2x3 + 10x2 + x) - 3.

Multiply all terms by 10 it then becomes 10x2+13x+4 = (5x+4)(2x+1) when factored.

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