It can't be factored because its discriminant is less than zero.
That doesn't factor neatly. Applying the quadratic equation, we find two real solutions: (31 plus or minus the square root of 401) divided by 20x = 2.5512492197250394x = 0.5487507802749606
(5x - 4)(2x + 3)
10x2 - 64 = 36 + 6x2; whence, 4x2 - 100 = 0, x2 = 25, and x = ±5.
(x + 3)(x + 1)(x - 3)(x -1)
10x2 + 101x + 10 = (10x + 1)(x + 10)
4x3+10x2+2x+5= (2x+5)(2x2+1)
The answer is 21
If that's - 94x, the answer is 2(3x - 10)(x2 + 5x + 1)
10x2 - 20xz + 15xy = 5x (2x - 4z + 3y)
If: 10x2-64 = 36+6x2 Then: 4x2-100 = 0 And: (2x-10)(2x+10) = 0 So: x = 5 or x = -5
This polynomial doesn't factor. The only thing you can do is take out parts of some terms, e.g. 2(2x3 + 10x2 + x) - 3.
Multiply all terms by 10 it then becomes 10x2+13x+4 = (5x+4)(2x+1) when factored.