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A rectangle has an area 56 yards and a length of 8 yards what is the width?
The width is 7 yards. Area = length x width 56 = 8 x ? 56 = 8 x 7
The length of a new rectangle playing field is 8 yards longer than quadruple the width If the perimeter of the rectangle playing field is 496 yards What are its dimensions?
The length is 200 yards and the width is 48 yards.length + width = 248 yards, and length = (4 x width) + 8 yards.substituting (4 x width) + 8 yards for length,(4 x width) + 8 yards + width = 248 yards;simplifying, width = 240/5 yards = 48 yards;then length = 248 - 48 yards = 200 yards
Find the area of a rectangle that has the length of four yards and a width of 3 yards?
Area = Length x Width so... 4 yards x 3 yards = 12 square yards
What is 1200mm x 900mm in feet?
1200mm x 900mm is equal to 3.94 feet x 2.95 feet.
What is the size of a 100 square yards?
10yards x 10yards or 4 yards x 25 yards or 20 yards x 5 yards and so on. Width x length.
What is the length of a rectangle garden is 2 yards greater than the width the area is 80 square yards. Find the length and width?
Area = Length * Width Make both X X = width X + 2 = Length X(X+2) = 80 X^2 + 2X = 80 X^2 + 2X -80 = 0 Easy factoring (X-8)(X+10) no negative lengths or widths, so Length = 10 yards Width = 8 yards
What is the volume of a box with a length of 4 yards a width of 4 yards and the height of 3 yards?
The formula for the volume of a "box" is length x width x height.In this case, we have 4 yds x 4 yds x 3 yds = 48 cubic yards.
What is length x width of 1 sq yard?
There are an infinite number of solutions. Assuming that length is at least as great as the width, the length can take any value greater or equal to 1 yard. If the length is x yards, then the width is 1/x yards. For example, 50 yards * 1/50 yards or 1050 yards * 10-50 yards are possible solutions.
The length of a rectangular field is 75 yards longer than twice the width If the area of the field is 4050 square yards what is the length and width of the field?
Let the length be (2x+75) and the width be x: length*width = area in square yards (2x+75)*x = 4050 2x2+75x-4050 = 0 Solving the above quadratic equation works out as: x = -67.5 or x = 30 it must be the latter because dimensions can't be negative. Therefore: length = 135 yards and width = 30 yards Check: 135*30 = 4050 square yards
How to figure cement in yards?
length x width x height= cubic feet cubic feet/27= cubic yards
What is the area of a rectangle with the width of three fourth yards and length of two fifth yards?
Area=Length x width so you have: A=(2/5)*(3/4) A=(2*3)/(5*4) A=6/20 A=.3 yards^2 Your answer is yards squared because you are multiplying yards x yards.
How do you measure area for cubic yards for concrete footings?
Length x Width x Depth
