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That factors to (x^3 + 64)(x^3 + 64) which factors to (x + 4)(x + 4)(x^2 - 4x + 16)(x^2 - 4x + 16)

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X6 plus 3x4-x2-3 equals 0?

x6 + 3x4 - x2 - 3 = 0(x6 + 3x4) - (x2 + 3) = 0x4(x2 + 3) - (x2 + 3) = 0(x2 + 3)(x4 - 1) = 0(x2 + 3)[(x2)2 - 12] = 0(x2 + 3)(x2 + 1)(x2 - 1) = 0(x2 + 3)(x2 + 1)(x + 1)(x - 1) = 0x2 + 3 = 0 or x2 + 1 = 0 or x + 1 = 0 or x - 1 = 0x2 + 3 = 0x2 = -3x = ±√-3 = ±i√3 ≈ ±1.7ix2 + 1 = 0x2 = -1x = ±√-1 = ±i√1 ≈ ±ix + 1 = 0x = -1x - 1 = 0x = 1The solutions are x = ±1, ±i, ±1.7i.


Why you should apply the technique of difference of two cubes in the example x raised to the power of 6-x raised to the power of 6?

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What is 6874678576 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 minus 6874678576?

Answer: 0


What is 0 plus 2?

The sum of 2 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 equals 2.