Q: What is x6 plus 128x3 plus 4096 0?

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If you mean: 3y-x = 6 then the x intercept is at (-6, 0)

31

0, 1 and any number that is a 12th power.

Is this a trick-question? 1+0+0+8=9

(2x6 - 128) 2(x6 - 64) 2(x6 - 26 ) 2 (x3 - 23)(x3 + 23) x=2 ans The answer above is correct to 2(x6-26) 26√(x6-26) 2(x-6√2)3(x+6√2)3 2(x-1.1224620483093729814335330496792)3(x+1.1224620483093729814335330496792)3 Therefore, if that equation equals to 0, x=±1.1224620483093729814335330496792

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x6 + 3x4 - x2 - 3 = 0(x6 + 3x4) - (x2 + 3) = 0x4(x2 + 3) - (x2 + 3) = 0(x2 + 3)(x4 - 1) = 0(x2 + 3)[(x2)2 - 12] = 0(x2 + 3)(x2 + 1)(x2 - 1) = 0(x2 + 3)(x2 + 1)(x + 1)(x - 1) = 0x2 + 3 = 0 or x2 + 1 = 0 or x + 1 = 0 or x - 1 = 0x2 + 3 = 0x2 = -3x = ±√-3 = ±i√3 ≈ ±1.7ix2 + 1 = 0x2 = -1x = ±√-1 = ±i√1 ≈ ±ix + 1 = 0x = -1x - 1 = 0x = 1The solutions are x = ±1, ±i, ±1.7i.

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Answer: 0

The sum of 2 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 equals 2.