That factors to (x^3 + 64)(x^3 + 64) which factors to (x + 4)(x + 4)(x^2 - 4x + 16)(x^2 - 4x + 16)
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If you mean: 3y-x = 6 then the x intercept is at (-6, 0)
0, 1 and any number that is a 12th power.
Is this a trick-question? 1+0+0+8=9
(2x6 - 128) 2(x6 - 64) 2(x6 - 26 ) 2 (x3 - 23)(x3 + 23) x=2 ans The answer above is correct to 2(x6-26) 26√(x6-26) 2(x-6√2)3(x+6√2)3 2(x-1.1224620483093729814335330496792)3(x+1.1224620483093729814335330496792)3 Therefore, if that equation equals to 0, x=±1.1224620483093729814335330496792