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That factors to (x^3 + 64)(x^3 + 64) which factors to (x + 4)(x + 4)(x^2 - 4x + 16)(x^2 - 4x + 16)

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X6 plus 3x4-x2-3 equals 0?

x6 + 3x4 - x2 - 3 = 0(x6 + 3x4) - (x2 + 3) = 0x4(x2 + 3) - (x2 + 3) = 0(x2 + 3)(x4 - 1) = 0(x2 + 3)[(x2)2 - 12] = 0(x2 + 3)(x2 + 1)(x2 - 1) = 0(x2 + 3)(x2 + 1)(x + 1)(x - 1) = 0x2 + 3 = 0 or x2 + 1 = 0 or x + 1 = 0 or x - 1 = 0x2 + 3 = 0x2 = -3x = ±√-3 = ±i√3 ≈ ±1.7ix2 + 1 = 0x2 = -1x = ±√-1 = ±i√1 ≈ ±ix + 1 = 0x = -1x - 1 = 0x = 1The solutions are x = ±1, ±i, ±1.7i.


Why you should apply the technique of difference of two cubes in the example x raised to the power of 6-x raised to the power of 6?

0


What is 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0?

0 plus 0 plus 0, repeated multiple times, equals 0. Adding zero to zero does not change the value, so regardless of how many times you add it, the sum remains 0. Therefore, the final result is simply 0.


What is 6874678576 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 minus 6874678576?

Answer: 0