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(2x6 - 128)

2(x6 - 64)

2(x6 - 26 )

2 (x3 - 23)(x3 + 23)

x=2 ans

The answer above is correct to

2(x6-26)

26√(x6-26)

2(x-6√2)3(x+6√2)3

2(x-1.1224620483093729814335330496792)3(x+1.1224620483093729814335330496792)3

Therefore, if that equation equals to 0, x=±1.1224620483093729814335330496792

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