0
(2x6 - 128)
2(x6 - 64)
2(x6 - 26 )
2 (x3 - 23)(x3 + 23)
x=2 ans
The answer above is correct to
2(x6-26)
26√(x6-26)
2(x-6√2)3(x+6√2)3
2(x-1.1224620483093729814335330496792)3(x+1.1224620483093729814335330496792)3
Therefore, if that equation equals to 0, x=±1.1224620483093729814335330496792
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