If you know that "sin(x)sin(x)=1", this must mean that just sin(x)=1 or -1, since sin(x) can take any value between -1 and 1, but both must be the same in order for "1" to be the product.
Now, plot a regular sin(x) curve, and find all the possible points where sin(x)= 1 or -1. These are your x values.
NO, sinxtanx=sinxsinx/cosx since tanx is sinx/cosx this is sin^2xcosx now add cosx cosx(sin^2x+1) after factoring Does this equal tanx? No, since this would require tanx to equal cosx(sin^2x+1) and it does not.
(1 + tanx)/sinxMultiply by sinx/sinxsinx + tanxsinxDivide by sin2x (1/sin2x) = cscxcscx + tan(x)csc(x)tanx = sinx/cosx and cscx = 1/sinxcscx + (sinx/cosx)(1/sinx)sinx cancels outcscx + 1/cosx1/cosx = secxcscx + secx
solution: y = 0 x = -1
The value of x that satisfies -9 multiplied by x equals 1 is x = -1/9.
1
x = -1
If [ y = x + 2 ], then x is not -1 when y = 5.If [ y = x + 2 ],then when x = -1, y = 1,and when y = 5, x = 3.
x=-1/2
1+x=dd+x so dd=1 so d=1 1+x=89b+x so 89b=1 so b=1/89 bc+x=1+x so bc=1 so c=1/(1/89) = 89 so cd=89 (and x=88)
If 1 multiplied by X equals 8, then X equals 8.
In the equations Y=X-1 and Y=-X+1, the solution is (1,0)
f(x) = 2*(x-3)*(x+2)/(x-1) for x ≠1