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(1 + tanx)/sinx

Multiply by sinx/sinx

sinx + tanxsinx

Divide by sin2x (1/sin2x) = cscx

cscx + tan(x)csc(x)

tanx = sinx/cosx and cscx = 1/sinx

cscx + (sinx/cosx)(1/sinx)

sinx cancels out

cscx + 1/cosx

1/cosx = secx

cscx + secx

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Q: Parenthesis 1 plus tanx end parenthesis divided by sinx equals cscx plus secx?
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