It is: (x-5)(x+1) when factored
(4x + 5)(x - 3)
4x2 - x - 5 = 0 4x2 + 4x - 5x - 5 = 0 4x(x + 1) - 5(x + 1) = 0 (4x - 5)(x + 1) = 0 4x - 5 = 0 or x + 1 = 0 4x = 5 or x = -1 x = 5/4 o x = -1
x^2 + 4x + 5 cannot be factored because its discriminant is less than zero.
Find factors of -5 that can be added to make -4, in this case -5 and 1, so: (x - 5)(x + 1) = x2 - 4x - 5
x2 - 4x - 5 = zero( x - 5 ) ( x + 1 ) = zerox - 5 = zero ...... X = 5x + 1 = Zero ...... X = -1
When you multiply 4x² by 4x², you multiply the coefficients (4 * 4 = 16) and add the exponents of the variables (x² * x² = x^(2+2) = x⁴). Therefore, the result is 16x⁴.
x2 + 4x = x(x + 4)
x2 + 4x = x(x+4)
4x^2 = 2 * 2 * x * x
(4x - 7y)(4x + 7y)
X2 - 4X - 5 = 0 easy factor, what two factors of - 5 add up to - 4 (X + 1)(X - 5) X = - 1 ------------- X = 5 --------------
(4x-5)(4x+5)