Find factors of -5 that can be added to make -4, in this case -5 and 1, so:
(x - 5)(x + 1) = x2 - 4x - 5
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8x^2 + 6x - 5 = 8x^2 + 10x - 4x - 5 = 2x * (4x + 5) - (4x + 5) = (2x -1) * (4x + 5)
(3x + 1)(x - 5)
4x2 - x - 5 = 0 4x2 + 4x - 5x - 5 = 0 4x(x + 1) - 5(x + 1) = 0 (4x - 5)(x + 1) = 0 4x - 5 = 0 or x + 1 = 0 4x = 5 or x = -1 x = 5/4 o x = -1
(x - 5)(x + 12)
if you mean (3/(2x-5))(21/(8x2-14x-15)) you would get (63/( (2x-5)(4x+3)(2x-5) ) simplified more would be 63/ ( (2x-5)2(4x+3) )