This kind of question is tricky, because average velocity is not simply the average OF the velocities. The reason is you spend more time driving the slower part.
The correct approach is to compute (average velocity) = (total distance) / (total time)
Total distance = 232 + 232 km.
Total time = (time going 46 km/h) + (time going 70 km/h)
The above terms are found by computing distance/speed:
at 46 km/h, it takes (232 km) / (46 km/h) = (232/46) hours
etc. - you can finish the details.
total velocity * * * * * It is the average speed, not velocity which is a vector.
a high speed train travels south for 2.00 h for a distance of 454km. what is its average velocity?
The definition of speed is the size/magnitude/measure of an object's velocity. Average speed = distance divided by time
velocity is a vector and speed is scalar. Velocity has magnitude and directions, with magnitude being speed. The magnitude of average velocity and average speed is the same.
In physics, total distance/TIME is average speed, so this is false. Velocity should be switched out with TIME.
Distance = time * average speed (velocity) Average speed = Distance/time
No. Average speed is.
No. Average velocity is still a velocity.Distance is a product of (a velocity or speed) times (a length of time).
Acceleration equals velocity divided by time i.e a=v/t The S.I unit of Acceleration is m/s2
The velocity of the object. Velocity involves direction as well as size (the concept of speed does not involve direction) e.g. I can drive round a roundabout at a constant speed of 30 m.p.h., but in doing so my direction continually changes, so my velocity keeps changing
total velocity * * * * * It is the average speed, not velocity which is a vector.
Speed is the magnitude of distance travelled per unit time, whereas velocity depends on the magnitude of distance travelled as well as the direction of motion. Speed is a scalar quantity, velocity is a vector. Speed cannot be negative, velocity can be negative. Average speed of an object after travelling a certain distance is always non-zero, but for velocity the average velocity can be zero (this follows from the previous idea).
Average speed = 1/2 (initial speed + final speed) Time = (distance)/(average speed)
Velocity = Distance ÷ Time : therefore Time = Distance ÷ Velocity. If the average speed is 50mph then Time = 550 ÷ 50 = 11 hours. If the average speed is 70mph then Time = 550 ÷ 70 = 7.86 hours (7 hours 52 minutes approximately)
a high speed train travels south for 2.00 h for a distance of 454km. what is its average velocity?
Yes, since velocity is speed and direction its average can be zero. For example say a plane flies from point A to point B at 300 mph and turns around to go from B to A at 300 mph; its average velocity is 0 since it is in the same spot as it started ( the velocity vectors cancel) but its average speed is 300 mph.
Time taken = Distance ÷ Speed (or Velocity) Example : If the average speed for the journey was 56 mph then it would take :- 1065 ÷ 56 = 19.02 hours approx.