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What is three times a number z increased by 4?
3z+4
What is z times the quantity of three plus 4?
Zx(3+4)= Zx7 = 7z the answer is 7z
What is z sqared minus 5z plus 4 equal zero?
Z2 - 5Z + 4 = 0 (Z- 1)(Z - 4) so, Z = 1 ---------- and Z = 4 -----------
What is the solution of equation 4 x z equals 28?
4 x z = 28 z = 28/4 z = 7
What is the pattern -4 -9 -16 -25 -36 -x -y -z -100?
2*-2, 3*-3,4*-4,etc. * is a times sign.
What is three times a number z increased by 4?
3z+4
If Negative 9 times z plus 4 equals Negative 5 what does z equal?
Z= -1
What is the answer for twenty-four x times xy times y times z times z times z times z times z?
24x2y2z5
What is z times the quantity of three plus 4?
Zx(3+4)= Zx7 = 7z the answer is 7z
There were 4 times as many adults y as children 4 and half times as many seniors z as adults y write expressions for the number of children and the number of seniors in terms of the number if adults?
Suppose there were x children. Then y = 4*x Therefore x = y/4. Also, z = 4.5*x so that 2*z = 9*x = 9*(y/4) so that 8*z = 9*y or z = 8/9*y
What is z times z in trig?
z^2
What is z sqared minus 5z plus 4 equal zero?
Z2 - 5Z + 4 = 0 (Z- 1)(Z - 4) so, Z = 1 ---------- and Z = 4 -----------
Factor z times z plus 1?
Z + or - i and z-1
What is the solution of equation 4 x z equals 28?
4 x z = 28 z = 28/4 z = 7
Is your proof about Fermat true or false?
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appy&Peace. Trantancuong.
Marcia has 84 less than three times as much as Sue together they have 132 how much money does Marcia have?
Sue has Z. Marcia has (3Z - 84), three times as much as Sue, minus 84. Together their amounts equal 132. So, The amount Sue has plus the amount Marcia has is 132 or, Z + (3Z - 84) = 132 Then, Z + 3Z = 132 + 84 (minus 84 from one side of the expression, and add it to the other side) Z + 3Z = 216 (Z + 3Z)/Z = 216/Z (divide both sides by Z to get one Z on one side) Z/Z + 3Z/Z = 216/Z (or written like this) 1 + 3 = 216/Z 4 = 216/Z 4 x Z = (216/Z) x Z (multiply both sides by Z) 4Z = 216 4Z/4 = 216/4 (divide by 4 to isolate Z) Z = 54 So, Sue has 54, therefore if Marcia has (3Z - 84), then 3 x 54 - 84, which is 78. So, Marcia has 78 We can check that together, 54 plus 78 equals 132.
Expand z plus 11 times z plus 11?
Expand z plus 11 times z plus 11 = (z+11)(z+11) = z2 + 22z + 121.
