z2 = z * z * 1; z = z * 1. Greatest common factor is z.
It is Z.
(z - 4)(x + y)
If z = a + ib then arg(z) = arctan(b/a) Let z' denote the conjugate of z. Therefore, z' = a - ib Then arg(z') = arctan(-b/a) = 2*pi - arctan(b/a) = 2*pi - arg(z)
The greatest common factor of 6 and 9 is not 5.
(z - 6)(z - 6)
(z + 1)(y + x)
Ten z plus one, or ten z plus ten. That depends on where you had parentheses in the original expression: (10 * z) +1 = 10z + 110 * (z + 1) = 10z + 10
(z + 15)(z + 3)
Expand z plus 11 times z plus 11 = (z+11)(z+11) = z2 + 22z + 121.
Z= -1
7+7z 7=7*1 7z=7*z 7(1+z) is factored form
3z2 + 45z + 42 = 3(z2 + 15z + 14) = 3(z + 1)(z + 14).
-16
z2 = z * z * 1; z = z * 1. Greatest common factor is z.
y(z+x) + 4(x+z)
xz + x + yz + y = (x + y)(z + 1)