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The volume is 0,046 L.
V = k*T/P Apart from the fact that a change in temperature from 20C to 80C cannot be described as a reduction, V2 = V1 * T2P1/T1P2 = 500*(273.15+80)*420/[(273.15+20)*650] = 500*353.15*420/(293.15*650) = 289.2 mL
If your talking about vacuum 500 microns of Hg is lower.
Mercury is a metal element. Atomic mass of it is 200.
The atomic mass is 201 (rounded to whole numbers). Is that what you needed?
1 gram = 1 mL so;500 g = 500 mL34
The volume is 0,046 L.
0.05 L
8.10 L
V = k*T/P Apart from the fact that a change in temperature from 20C to 80C cannot be described as a reduction, V2 = V1 * T2P1/T1P2 = 500*(273.15+80)*420/[(273.15+20)*650] = 500*353.15*420/(293.15*650) = 289.2 mL
7.41 L
The gas would occupy 40 liters of space, by volume. This is only true as long as the conditions were normal.
I'm not going to do all your work. The formula is Pressure1 X Volume 1 X Temperaure 1(in Kelvins)= Pressure 2 X Volume 2 X temperaure 2 So 3.97L X 1479mm Hg X 231.15K = y volume X 760mm Hg (1 atmosphere) X 293.15 (20 degrees C) I'll let you figure out the maths.
500
If your talking about vacuum 500 microns of Hg is lower.
the answer is 72.1 Hg
Mercury (Hg) has an atomic mass of 200.59