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What volume will 500 mL of gas at 20 c and a pressure of 420 mm Hg occupy if the temperature is reduced to 80 c and the pressure increased to 650 mm Hg?
Wiki User
∙ 11y ago
V = k*T/P
Apart from the fact that a change in temperature from 20C to 80C cannot be described as a reduction,
V2 = V1 * T2P1/T1P2
= 500*(273.15+80)*420/[(273.15+20)*650]
= 500*353.15*420/(293.15*650)
= 289.2 mL
Wiki User
∙ 11y ago
Wiki User
∙ 12y ago490ml
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