To find the multiples of 10 that are factors of 280, we need to identify the factors of 280 first. The factors of 280 are 1, 2, 4, 5, 7, 8, 10, 14, 20, 28, 35, 40, 56, 70, 140, and 280. Among these factors, the multiples of 10 are 10, 20, 40, 70, and 140. Therefore, the multiples of 10 that are factors of 280 are 10, 20, 40, 70, and 140.
They are: 5, 10 and 20
The factors of 80 are: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80 Those which are multiples of 4 are: 4, 8, 16, 20, 40, 80
There are infinetly many numbers which have 2 and 5 as their factors. Some examples are 10, 20, 30, 40, etc. 2 and 5 both are prime numbers and their common multiples are the multiples of 2 x 5 = 10. So all the multiples of 10 have 2 and 5 as their factors. However if consider 2 and 5 as the only two proper factors, then the required number is 10.
What are the odd multiples of 3 between 10 and 40? 15, 21, 27, 33, 39. What multiples of 10 is 34 between?
40 is the least number that is a multiple of 4 and 10. all multiples of 40 are multiples of 4 and 10 as well
No number has the multiples of 1, 2, 4, 5, 8, 10, 16, 20, 40, 80, but the number 80 (and all its multiples: 160, 240, 320, 400, ...) has them all as FACTORS.
2 and 5 are the prime factors that are common to all multiples of 10.
No.
This is a nonsensical question. There are more than 13 multiples of 10 - in fact there are an infinite number. And there are multiples of 10 which have an infinite number of factors - so there cannot be a "largest" number of factors.
The first 4 multiples of 10 are: 10, 20, 30, and 40.
A multiple of a number is in that number's times table. For example, a multiple of 10 will be in the 10 times table. 30 = 10x3 40 = 10x4 Therefore, 30 and 40 are multiples of 10