You refer to a "rectangular" bottom, but we know that a circle offers the most area for a given perimeter, so the height of the rectangular part should be 0. We really just want a semicircle with a perimeter of 12 meters.
π·d/2 + d = 12 m
(π/2 + 1)·d = 12 m
d = 12 m / (π/2 + 1) = ~4.6678 m
The answer could be 1260 cubic metres - but only if the three given numbers refer to the lateral dimensions of a cuboid.
6 meters squared
12mtr. x 5mtr. = 60 sq. mtr.
approximately 53 meters
Surface area of sphere: 4*pi*6 squared = 452.389 square meters rounded to 3 decimal places
The answer could be 1260 cubic metres - but only if the three given numbers refer to the lateral dimensions of a cuboid.
12meters
12 meters y
12meters
.7 kg. Kilograms are a measure of mass.
It depends on how much weight you put in it
It is: 12+8+12+8 = 40 meters
6 meters squared
12mtr. x 5mtr. = 60 sq. mtr.
There are 12000 millimetres in 12 metres.
Calculation of deceleration the speeds at two points in time.
approximately 53 meters