Calculation of deceleration the speeds at two points in time.
Takes her 60 seconds to do what? Travel 1 mile? Travel 10 miles?
7.5
The answer will depend on its acceleration.
Without knowing some of the conditions that led up to the situation at 9 seconds, I'm afraid there's no way to figure that out. By the way, once you know the 'velocity', you know the 'direction'. 'Velocity' means speed and direction. It's not just a big technical-sounding word for 'speed'.
0.8633 seconds
you doing homework???
You need more details.The final velocity could be 0However, you need to know the initial velocity, and the braking acceleration, and perhaps other acceleration/deceleration factors to know the true answer.
The initial velocity is 10 meters/sec and is thrown up against the gravitational pull of the earth. This means that the ball is experiencing a deceleration at the rate of 9.8 meters/sec/sec to bring its final velocity to zero. v^2 - u^2 = 2gs where u is the initial velocity, v the final velocity, g is the acceleration or deceleration, and s is the distance traveled. 0^2 - 10^2 = 2 x (-9.8) x s -100 = -19.6s 100 = 19.6s s = 100/19.6 = 5.102 meters Now v = u + gt where v is the final velocity, u is the initial velocty, g is the acceleration or deceleration, and t is the time. When the ball is thrown up with 10 meters/sec velocity it is acted upon by the deceleration of gravity until its velocity becomes zero. So 0 = 10 - 9.8t or 9.8t = 10 t = 1.020 seconds The time for the ball to go up is 1.020 seconds and the same time is taken for the ball to come back for a total of 2.040 seconds.
Velocity increases after 5 seconds
Velocity is derived by dividing displacement with time in seconds
The change in velocity is 51-100 = -49 m/s This occurred over a period of 5 seconds so The (negative) acceleration - aka - deceleration is (-49 m/s)/(5 s) = -9.8 m/s²
35/s-2
That depends on its rate of deceleration. And the rate of deceleration depends on the quality of the brakes, the friction of the road and the tires, if it is raining, snowing, black iced, sand, gravel, cement, black top, ect. Lots of variables. But let's say that the deceleration is 5 miles/second squared, to make it real easy. You find how many seconds are in a minute, and how many minutes are in an hour. Let me do the math for you, 60/60/60, now multiply that by our velocity, 55. 60/60/60*55 = .91666667 miles per second. Divide current velocity (.9166666667) by rate of decelration (5 mi/sec squared) and you get your answer in seconds. I just made that problem up. In real life, that sounds incredibly unrealistic. This question would be much more complete if you had the rate of deceleration in the question.
The velocity changes from [ V upward ] to [ V downward ].The total change in velocity is [ 2V ].Acceleration = (change in velocity) divided by (time for the change) = 2V/6But the acceleration is just the acceleration of gravity = 9.8 meters / sec2 .9.8 = 2V / 62V = 58.8V = 29.4 meters per second upward
Constant speed and constant velocity
The velocity = (location at 40 seconds - location at 20 seconds)/20 in the direction in which the object is moving.
The duration of WWE Velocity is 2760.0 seconds.