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Calculation of deceleration the speeds at two points in time.

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A plane traveling at 80 ms lands on a runway and comes to rest after 10 seconds What was the plane's deceleration?

The plane's deceleration can be calculated using the equation: acceleration = change in velocity / time taken. The plane's initial velocity is 80 m/s, final velocity is 0 m/s, and time taken is 10 seconds. Therefore, the deceleration is 8 m/s^2.


What is the deceleration of a car traveling with a velocity of 30 meters per second slowing down to a velocity of 10 meters per second within 10 seconds?

you doing homework???


How A speed boat moving at a velocity of 25 ms runs out of gas and drifts to a stop 3 minutes later 100 meters away. What is its rate of deceleration?

To find the rate of deceleration, we first need to convert the time from minutes to seconds. 3 minutes = 180 seconds. Next, we use the equation of motion: final velocity^2 = initial velocity^2 + 2 * acceleration * distance. Since the boat comes to a stop, the final velocity is 0 m/s. Substituting the values and solving for acceleration, we get a deceleration rate of 0.139 m/s^2.


If an archer shoots an arrow straight up with an initial velocity magnitude of 100.0 ms After 5.00 seconds the velocity is 51.0 ms. At what rate is the arrow decelerated?

The average deceleration of the arrow can be calculated using the formula: average deceleration = (final velocity - initial velocity) / time. Plugging in the values gives an average deceleration of (51.0 - 100.0) / 5.00 = -9.8 m/s^2. This negative value indicates that the arrow is decelerating due to the acceleration of gravity.


A braking time of 1.5 to 2 seconds what is the final velocity?

You need more details.The final velocity could be 0However, you need to know the initial velocity, and the braking acceleration, and perhaps other acceleration/deceleration factors to know the true answer.


A speed boat moving at a velocity of 25 m/s runs out of gas and drifts to a stop 3 minutes later 100 meters away. What is its rate of deceleration?

The initial velocity is 25 m/s, final velocity is 0 m/s, and the distance covered is 100 meters. Convert 3 minutes to seconds (3 minutes = 180 seconds). Use the equation v^2 = u^2 + 2as, where v is final velocity, u is initial velocity, a is acceleration, and s is distance. Solve for acceleration (deceleration in this case) to find it to be -0.3472 m/s^2. The negative sign indicates deceleration.


In A speed boat moving at a velocity of 25 ms runs out of gas and drifts to a stop 3 minutes later 100 meters away. What is its rate of deceleration?

To find the rate of deceleration, we need to first convert the time to seconds. 3 minutes is 180 seconds. Then, we can use the formula for acceleration: acceleration = change in velocity / time taken. The change in velocity is from 25 m/s to 0 m/s, which is -25 m/s (negative because it's decelerating). So, the rate of deceleration is -25 m/s / 180 s = -0.139 m/s².


When throwing a ball straight up when in the air with an initial velocity of 10 meters per second what high will it go and how long will it take to return to the ground?

The initial velocity is 10 meters/sec and is thrown up against the gravitational pull of the earth. This means that the ball is experiencing a deceleration at the rate of 9.8 meters/sec/sec to bring its final velocity to zero. v^2 - u^2 = 2gs where u is the initial velocity, v the final velocity, g is the acceleration or deceleration, and s is the distance traveled. 0^2 - 10^2 = 2 x (-9.8) x s -100 = -19.6s 100 = 19.6s s = 100/19.6 = 5.102 meters Now v = u + gt where v is the final velocity, u is the initial velocty, g is the acceleration or deceleration, and t is the time. When the ball is thrown up with 10 meters/sec velocity it is acted upon by the deceleration of gravity until its velocity becomes zero. So 0 = 10 - 9.8t or 9.8t = 10 t = 1.020 seconds The time for the ball to go up is 1.020 seconds and the same time is taken for the ball to come back for a total of 2.040 seconds.


A speed boat moving at a velocity of 25 ms runs out of gas and drifts to a stop 3 minutes later 100 meters away. What is its rate of deceleration?

The initial velocity was 25 m/s and it came to a stop over a distance of 100 meters in 3 minutes (180 seconds). To find the deceleration, use the equation v^2 = u^2 + 2as, where v is final velocity (0 m/s), u is initial velocity (25 m/s), a is acceleration, and s is distance. Solving for acceleration gives you approximately -0.35 m/s^2, indicating the boat's rate of deceleration.


A motorcycle slows down from 40 ms to 20 ms If this takes 4 seconds what is the motorcycle's acceleration?

Acceleration(a) = [final velocity(v) - initial velocity(u)] / time(s) Algebrtaically a = [ v - u ] / s A negative result indicates deceleration a = [20 - 40 ]= / 4 a = [-20] / 4 a = -5 m/s^(2) This is negative which matches the question of slowing down/deceleration.


What velocity does the student have after five seconds?

Velocity increases after 5 seconds


What is the velocity of a bicycle in meters per second if it travels 1 kilometers west in 4.1 minutes?

To convert 1 kilometer to meters, multiply by 1000. So, 1 kilometer is 1000 meters. To convert 4.1 minutes to seconds, multiply by 60. So, 4.1 minutes is 246 seconds. The velocity of the bicycle would be 1000 meters / 246 seconds = 4.07 meters per second west.