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Calculation of deceleration the speeds at two points in time.

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Q: What is the deceleration of a bicycle that travels from a velocity of 12meters per seconds in 2s?
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What is the deceleration of a car traveling with a velocity of 30 meters per second slowing down to a velocity of 10 meters per second within 10 seconds?

you doing homework???


A braking time of 1.5 to 2 seconds what is the final velocity?

You need more details.The final velocity could be 0However, you need to know the initial velocity, and the braking acceleration, and perhaps other acceleration/deceleration factors to know the true answer.


When throwing a ball straight up when in the air with an initial velocity of 10 meters per second what high will it go and how long will it take to return to the ground?

The initial velocity is 10 meters/sec and is thrown up against the gravitational pull of the earth. This means that the ball is experiencing a deceleration at the rate of 9.8 meters/sec/sec to bring its final velocity to zero. v^2 - u^2 = 2gs where u is the initial velocity, v the final velocity, g is the acceleration or deceleration, and s is the distance traveled. 0^2 - 10^2 = 2 x (-9.8) x s -100 = -19.6s 100 = 19.6s s = 100/19.6 = 5.102 meters Now v = u + gt where v is the final velocity, u is the initial velocty, g is the acceleration or deceleration, and t is the time. When the ball is thrown up with 10 meters/sec velocity it is acted upon by the deceleration of gravity until its velocity becomes zero. So 0 = 10 - 9.8t or 9.8t = 10 t = 1.020 seconds The time for the ball to go up is 1.020 seconds and the same time is taken for the ball to come back for a total of 2.040 seconds.


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How do you get the velocity?

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When an archer shoots an arrow straight up with an initial velocity magnitude of 100.0 ms. After 5.00 s the velocity is 51.0 ms. At what rate is the arrow decelerated?

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A ball thrown up vertically returns to the thrower after 6 seconds find the velocity with which it was thrown up?

The velocity changes from [ V upward ] to [ V downward ].The total change in velocity is [ 2V ].Acceleration = (change in velocity) divided by (time for the change) = 2V/6But the acceleration is just the acceleration of gravity = 9.8 meters / sec2 .9.8 = 2V / 62V = 58.8V = 29.4 meters per second upward


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