111
150 ÷ 9 = 16 r 6 → the first natural number between 150 and 300 divisible by 9 is 9 × 17 (=154)300 ÷ 9 = 33 r 3 → the last natural number between 150 and 300 divisible by 9 is 9 × 33 (=297)→ there are 33 - 17 + 1 = 17 natural numbers between 150 and 300 divisible by 9.
150
All of them but I assume you mean evenly divisible. 150. 150/2 is 75 150/3 is 50 and 150/10 is 15
There are 29 numbers between 1 and 150 that are divisible by five.
It is 120, 150, and 180.
You could be 121.
any number is divisible by another... not always evenly in this case 150/4=37.5
150.
There are 899 numbers between 100 and 1000. Every 6th number is divisible by 6. 899 divided by 6 is 149 and 5/6. The answer must be 149 or 150. The first number in that set is 102 (17 x 6). The last is 996 (166 x 6). 166 - 17 + 1 is 150. There are 150 numbers between 100 and 1000 that are divisible by 6.
There are six such numbers: 153, 162, 171, 180, 189, 198.
There are 17 numbers between 150 and 300 that are divisible by nine: 153, 162, 171, 180, 189, 198, 207, 216, 225, 234, 243, 252, 261, 270, 279, 288, 297.
Every 6th number beginning with 102. There are 150 of them, and the last one is 996.