There are 17 numbers between 150 and 300 that are divisible by nine: 153, 162, 171, 180, 189, 198, 207, 216, 225, 234, 243, 252, 261, 270, 279, 288, 297.
150 ÷ 9 = 16 r 6 → the first natural number between 150 and 300 divisible by 9 is 9 × 17 (=154)300 ÷ 9 = 33 r 3 → the last natural number between 150 and 300 divisible by 9 is 9 × 33 (=297)→ there are 33 - 17 + 1 = 17 natural numbers between 150 and 300 divisible by 9.
There are 29 numbers between 1 and 150 that are divisible by five.
150
20 of them.
150/8 = 18.75 so 18 numbers.
150 ÷ 9 = 16 r 6 → the first natural number between 150 and 300 divisible by 9 is 9 × 17 (=154)300 ÷ 9 = 33 r 3 → the last natural number between 150 and 300 divisible by 9 is 9 × 33 (=297)→ there are 33 - 17 + 1 = 17 natural numbers between 150 and 300 divisible by 9.
There are 29 numbers between 1 and 150 that are divisible by five.
111
150
All of them but I assume you mean evenly divisible. 150. 150/2 is 75 150/3 is 50 and 150/10 is 15
Well, darling, you simply divide the range by the divisor and add 1 if the starting number is divisible by the divisor. In this case, you divide 1000 by 6 and subtract the result of dividing 100 by 6. So, (1000/6) - (100/6) + 1 = 166 - 16 + 1 = 151 numbers between 100 and 1000 are divisible by 6. Hope that tickles your fancy!
20 of them.
It is 120, 150, and 180.
150/8 = 18.75 so 18 numbers.
Eight of them.
10 numbers
You could be 121.