They are all divisible by 1 which is their HCF
not one number goes into 6 and 7 unless it is 1. the numbers 1, 2, 3, and 6 go into 6. only 1 goes into 7 because 7 is a prime number
1, 2, 3, 6, 7, 14, 21, 42
3 goes into 7 twice. (2x3=6)
The number is 1.
210 is the number which is completely divisible by all of these numbers but not 4.
6
21
It is: 1
136
Only 1 can go into 7 and 6 without a remainder.
1
only need 7 and 6 as 3 already goes into 6 so 42 84 126 168 210 252 294 336 378 420 and so on ...