The 3 is in the hundreds place. Remember numbers are set up in the following way. Example: 9,614,200,369.2345 Billions, Hundred Millions, Ten Millions, Millions, Hundred Thousands, Ten Thousands, Thousands, Hundreds, Tens, Ones, Tenths, Hundredths, Thousandths, Ten Thousandths.
nine - look at the last number of any number and start counting as ones. Then move left and start counting as tens, then hundreds, thousands, ten thousands, hundred thousands, millions, ten millions, hundred millions, billions, ten billions, hundred billions, trillions, ten trillions, and finally hundred trillions. So 1,000,000,000 is one billion.
4,964,883 has all of these qualities.
428, plus any number of thousands, ten-thousands, hundred-thousands, millions, etc.,plus any fraction less than '1' .
There are SIX zeroes in 1 million: 1,000,000From the right you have ones, tens, hundreds, thousands, ten thousands, hundred thousands, millions, ten millions, hundred millions, billions, ect.
The number 19,955,623 has eight places. In order from right to left they are: ones, tens, hundreds, thousands, ten thousands, hundred thousands, and millions. The number 6 is third from the right and therefore occupies the hundreds place.
Divide the numbers into millions, thousands, and hundreds: 7,907,979. The 3 numbers on the right (979) are hundreds, the 3 numbers in the middle are thousands (907), and the number on the left is millions (7). So, it's seven million, nine hundred and seven thousand, nine hundred seventy-nine.
The number is seven hundred and eighty thousand.
135,792,468,000. Being read, this number is 135 billion, 792 million, 468 thousand. The ten millions place is in the millions range. Each section has a specific title, and within that title is 3 digits. And each digit is either numbered ones, tens, or hundreds. I'll write an example below: hundred billions, ten billions, one billions, hundred millions, ten millions, one millions, hundred thousands, ten thousands, one thousands, hundreds, tens, ones. So the answer to your question would be 9.