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Notwane F.C. was created in 1965.
The negative log of a number is the log of the number's reciprocal ('1' divided by the number).
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what if I give you the wrong answer
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The answer really depends on what number you are doubling. Let's say that you wish to double the number a (which we assume is greater than 0). If we're raising a to the nth power, then n must satisfy the following equation: an = 2a Taking the natural log on both sides, n log a = log (2a), n = log (2a) / log a. So if we double the number a, it is raised to the log (2a) / log a power.
The derivative of a log is as follows: 1 divided by xlnb Where x is the number beside the log Where b is the base of the log and ln is just the natural log.
Assuming working to base '10' , then Antilog 2.3909 is 10^(2.3909) = 245.9801149/ Remember for logarithms. log of a number is log(10)[number] Hence its antilog is 10^(log number).
To find anti log of a number enter the number as the exponent of 10.
The natural log of a number is some other number such that if you take e (2.718281828...) and raise it to that other number you would get the first number. Another way to say this is that a natural log is a log with base e. The common log of a number is some other number such that if you take 10 and raise it to that other number you would get the first number. The natural log base, e, is a special transcendental number, chosen so that the derivative (respect to x) of ex is equal to ex . In other words, the slope of a tangent line to the curve y = ex at point (x, ex) is equal to ex for all x
You cannot solve log x- 2 unless (i) log x - 2 is equal to some number or (ii) x is equal to some number.
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