The answer is LCM(11, 6, 9) = 198
A number that is divisible by 6 but not by 3 must be a multiple of 6 that is not a multiple of 3. Since 6 is a multiple of 3 (6 = 2 * 3), any multiple of 6 will also be a multiple of 3. Therefore, there is no number that is divisible by 6 but not by 3.
As 6 is divisible by 3, ANY dumber divisible by 6 is also therefore divisible by 3. Any number divisible by 3 is ALSO a multiple of 3.
No, 6 is not divisible by 148. In order for one number to be divisible by another, the first number must be a multiple of the second number. In this case, 6 is not a multiple of 148 as it is much smaller. Therefore, 6 is not divisible by 148.
Every number divisible by 6 is a multiple of two. So: 6, 12, 18, 24, 30
It is a multiple of 6. There are an nfinite number of them and so cannot be listed. Each of these will be divisible by 6 (by definition). They will also be divisible by 2 and 3.
198
11
If a number is divisible by 6, then it must also be divisible by all the factors of 6, because 6 is just a multiple of each of its factors.
A number is divisible by 3 if the sum of its digits is a multiple of 3. A number is divisible by 6 if the sum of its digits is a multiple of 3 and it's even. A number is divisible by 9 if the sum of its digits is a multiple of 9.
Any multiple of 6
Any multiple of 6.
How about 30