To determine if 78 is a multiple of 3, we can use the divisibility rule for 3. The rule states that if the sum of the digits of a number is divisible by 3, then the number itself is also divisible by 3. In this case, 7 + 8 = 15, which is divisible by 3. Therefore, 78 is indeed a multiple of 3.
No number that is a multiple of 3, can be a prime number. A prime number must only be divisible by itself and 1. It cannot be divisible by any other number. Therefore if it is a multiple of 3, then it must be divisible by 3 and hence, not a prime number.
It is a multiple of 6. There are an nfinite number of them and so cannot be listed. Each of these will be divisible by 6 (by definition). They will also be divisible by 2 and 3.
A number is divisible by 3 if the sum of its digits is a multiple of 3. A number is divisible by 6 if the sum of its digits is a multiple of 3 and it's even. A number is divisible by 9 if the sum of its digits is a multiple of 9.
If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9
Because 9 is a multiple of 3.
To determine if 78 is a multiple of 3, we can use the divisibility rule for 3. The rule states that if the sum of the digits of a number is divisible by 3, then the number itself is also divisible by 3. In this case, 7 + 8 = 15, which is divisible by 3. Therefore, 78 is indeed a multiple of 3.
If a number is divisible by 4, it also means that the same number is divisible by 2. But if the number ends in a 3, it can't be divisible by 2 and, to a further extent, can't be divisible by 4.
No number that is a multiple of 3, can be a prime number. A prime number must only be divisible by itself and 1. It cannot be divisible by any other number. Therefore if it is a multiple of 3, then it must be divisible by 3 and hence, not a prime number.
It is a multiple of 6. There are an nfinite number of them and so cannot be listed. Each of these will be divisible by 6 (by definition). They will also be divisible by 2 and 3.
A number is divisible by 3 if the sum of its digits is a multiple of 3. A number is divisible by 6 if the sum of its digits is a multiple of 3 and it's even. A number is divisible by 9 if the sum of its digits is a multiple of 9.
If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9
If a number is even, it's divisible by two. If the digits of a number add up to a multiple of 3, it's a multiple of 3. For example, 342 is divisible by 3 because 3 + 4 + 2 = 9 and 9 is divisible by 3.
Oh, dude, a factor of the sum of the digits being 3 or a multiple of 3 just means that if you add up all the digits in a number and it equals 3, or if that sum is a multiple of 3, then that number has a factor that fits the bill. So, like, if you have a number where the digits add up to 3, or 6, or 9, or any multiple of 3, you've got yourself a match! It's like finding a snack in your pantry that fits your cravings perfectly – it just works out, man.
Any number that is divisible by 3 is a multiple of 3.
a 3 digit number that is divisible by on is a three digit number that is a multiple of one.
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.