Yes. Any prime number greater than 100 has only itself in its prime factorization. Examples: The prime factorization of 101 is 101. The prime factorization of 109 is 109. The prime factorization of 127 is 127. The prime factorization of 311 is 311. The prime factorization of 691 is 691.
There is no prime factorization of 47 since it is a prime number. It's only factors are 1 and 47.
The only number that has only one factor is '1'. Every other number has at least two factors: '1' and itself. If there are no more than that, then the number is a prime number.
1 is not a prime number, so it wouldn't be present in any prime factorization. Prime numbers don't really have factorizations, that is, the factorization is the number itself. There are prime numbers greater than 100.
13 is a prime number so the only factors are 1 and itself.
233,357 is a prime number. Its only factors are 1, 233357
61 is a prime number. Its only factors are 1 and 61.
379 is a prime number. Its only factors are 1 and itself.
None. 31 is a prime number. Its only factors are 1 and itself.
None, 53 is a prime number. Its only factors are 1 and itself.
The number 313 is a prime number, which means it is only divisible by 1 and itself. Therefore, the prime factorization of 313 is simply 313 x 1. Prime factorization is the process of breaking down a number into its prime factors, but since 313 is already a prime number, it cannot be further factored.
no. Prime numbers have to have two, and only two, factors: 1 and itself.