No. 27 is not evenly divisible by 32.
The mass number of an atom is the sum of its protons and neutrons. Cobalt has an atomic number of 27, so it has 27 protons. If it has 32 neutrons, then the mass number would be 27 (protons) + 32 (neutrons) = 59.
32.
1 and 5/27
9x3=27 32-27= 5 3 5/9
32 is the minuend
315 ÷ 32 = 9 remainder 27
1 3 8 27 32 1x3 =3 3+5=8 8x3=27 27+5=32
32. 4x8= 32. They can both go into 32
It is: 27 because 3*3*3 = 27
The element cobalt has 27 protons. Since the sum of the number of protons and neutrons in your particular question is 59, the answer to what has 27 protons and 32 neutrons is the particular isotope of cobalt labeled 59Co. This is cobalt's only stable isotope.
32/27 = 15/27