arrange the no. ascending and use the formula (n+1)/2=nth number...arranged no. :20 23 25 25 27 27 27 29 31 35 37 41 43n is the number of the numbers...substitute: (13+1)/2= 7th no. from the arranged numbers...so the answer 27
There are 5 numbers in the ordered list: 5 6 8 25 31 So the middle position is [(1+5)/2] = 3 and the middle number is 8. 27 is greater than 8 so continue with the second half of the list. There are 2 number in the reduced ordered list: 25 31 So the middle position is number is [(1+2)/2] = [1.5] = 2 and the middle number is 31. 27 is smaller than 31 so continue with the first half of the reduced list. There is only 1 number left in the reduced ordered list: 25. Since it is not 27, the number being sought is not in the list.
25 is the only composite number out of 31, 29, 25, 23.
When put in order, the numbers are: 16, 18, 24, 25, 26, 27, 31, 32 and 2123. The median is the middle number, which is 26. If you mean the 2123 to be 21 and 23, then the numbers are: 16, 18, 21, 23, 24, 25, 26, 27, 31 and 32. In this case, there is an even amount of numbers, so the median is the value halfway between the two middle numbers. They are 24 and 25, so the median is 24.5 as your answer.
2*100 + 31*10 + 27*1 = 200 + 310 + 27 = 537
arrange the no. ascending and use the formula (n+1)/2=nth number...arranged no. :20 23 25 25 27 27 27 29 31 35 37 41 43n is the number of the numbers...substitute: (13+1)/2= 7th no. from the arranged numbers...so the answer 27
There are 5 numbers in the ordered list: 5 6 8 25 31 So the middle position is [(1+5)/2] = 3 and the middle number is 8. 27 is greater than 8 so continue with the second half of the list. There are 2 number in the reduced ordered list: 25 31 So the middle position is number is [(1+2)/2] = [1.5] = 2 and the middle number is 31. 27 is smaller than 31 so continue with the first half of the reduced list. There is only 1 number left in the reduced ordered list: 25. Since it is not 27, the number being sought is not in the list.
27 and 31 are prime.
31 + 24 + 28 + 33 + 28 + 27 + 25 = 196/7 = 28
27
39
21 23 25 27 29 31 33 35 37 39
The element with an atomic number between 27 and 31 is cobalt, with atomic number 27.
Jeopardy - 1984 27-31 was released on: USA: 25 October 2010
31 (the rest are all multiples of 3).
27
25 is the only composite number out of 31, 29, 25, 23.