Study guides

☆☆

Q: What numbers are divisible by 2 and 3 and 5 and 9?

Write your answer...

Submit

Still have questions?

Related questions

Odd numbers are integers (whole numbers) that are not divisible by 2: 1, 3, 5, 7, ..., -1, -3, -5, -7...Odd numbers are integers (whole numbers) that are not divisible by 2: 1, 3, 5, 7, ..., -1, -3, -5, -7...Odd numbers are integers (whole numbers) that are not divisible by 2: 1, 3, 5, 7, ..., -1, -3, -5, -7...Odd numbers are integers (whole numbers) that are not divisible by 2: 1, 3, 5, 7, ..., -1, -3, -5, -7...

There are no such numbers.

All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.

2: 1 and 2 3: 1 and 3 5: 1 and 5

No odd numbers are evenly divisible by 2. 3 ÷ 2 = 1 1/2 11 ÷ 2 = 5 1/2

no. in order for a number to be divisible by 3 its numbers have to have a sum of a number divisible by 3. EX. (302) 3+0+2 = 5. 5 is not divisible by 3. Therefore 302 is not divisible by 3.

It is divisible by all of those numbers.

No. 50 is divisible by these numbers: 1, 2, 5, 10, 25, 50.

yes it is divisible by all of those numbers

There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.

3, 5, 7. 4, 6, and 8 are divisible by 2. 9 is divisible by 3.

Yes. The prime factorization of 75 is 3 x 5 x 5. So 75 is divisible by the two prime numbers 3 and 5.

Eight is divisible, out of these numbers, by only 2.

90 is composite. 90 = 2 * 3 * 3 * 5 = 2 * 32 * 5

Infinitely many.

Multiples of 60.

6 (15,30,45,60,75,90)

no.. heres a trick: if you add together the numbers (5+2+4) and that answer equals a number that is divisible by 3 then the number is divisible by three 5+2+4=11 11 is not divisible by 3 therefore, 524 is not divisible by 3

because 10 is also divisible by 2 and 5.

Last digit (0) is even, so it is divisible by 2 4 + 3 + 2 + 0 = 9 which is divisible by 3, so it is divisible by 3 last digit is 0 or 5, so it is divisible by 5 4 + 3 + 2 + 0 = 9 which is divisible by 9, so it is divisible by 9 last digit is 0, so it is divisible by 10 → 4320 is divisible by all the numbers 2, 3, 5, 9, 10

None of the numbers you listed are evenly divisible by 1000.

No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9

No, but I suspect you want to know if 186624 is divisible by those numbers. Out of that list, 186624 is divisible by all but 5.

No. It is divisible by these numbers: 1, 2, 5, 10, 79, 158, 395, 790.

Prime numbers are only divisible by 1 and itself... so no prime number can be divisible by the numbers you listed.