Because 4 and 5 are relatively prime, meaning that their greatest common factor is one, their least common multiple is 4*5, which is 20. So any number divisible by 20 is divisible by 5 and 4.
A Venn diagram for numbers divisible by both 4 and 5 would have two overlapping circles. One circle would represent numbers divisible by 4, while the other circle would represent numbers divisible by 5. The overlapping region where the two circles intersect would represent numbers divisible by both 4 and 5. This intersection would include numbers that are multiples of both 4 and 5, such as 20, 40, 60, and so on.
Numbers that are divisible by both 4 and 5 are multiples of the least common multiple of 4 and 5, which is 20. Therefore, numbers that are divisible by 4 and 5 are multiples of 20. In other words, any number that can be expressed as 20 multiplied by an integer (e.g., 20, 40, 60, 80, etc.) is divisible by both 4 and 5.
There are 278 5-digit numbers less than 20,000 that are divisible by both four and nine.
The numbers 20 and 40 are both multiples of 10, as they can be divided evenly by 10. They are also both even numbers, ending in 0. Additionally, both numbers are divisible by 5, as they end in 0.
To be divisible by both 4 and 5, the number has to be divisible by 20. Therefore, there are 12 numbers between 1 and 240, inclusive, which are divisible by 4 and 5: 20, 40, 60, 80, 100, 120, 140, 160, 180, 200, 220, 240.
There are infinitely many numbers divisible by 5 and 4. 680 is one of them.
740 is divisible by both 4 and 5.
All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.
Since both 3 and 5 are prime numbers, only numbers that are multiples of its product are the numbers that are divisible by both. 15 is the LCM of 3 and 5 and hence all multiples of 15 are divisible by both 3 and 5
90
40
345 and 218