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Numbers that are divisible by both 4 and 5 are multiples of the least common multiple of 4 and 5, which is 20. Therefore, numbers that are divisible by 4 and 5 are multiples of 20. In other words, any number that can be expressed as 20 multiplied by an integer (e.g., 20, 40, 60, 80, etc.) is divisible by both 4 and 5.
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DevinWell, honey, numbers that are divisible by 4 and 5 are simply multiples of their least common multiple, which is 20. So, any number that can be divided by both 4 and 5 without a remainder is fair game. Just think of it as the love child of 4 and 5, born to make your math problems a little less complicated.
The answer is twenty but there are many more.
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Is 20 a prime number?
No. Even numbers are never prime numbers. A prime number is a number that is only divisible by 1 and itself. Even numbers are always divisible by 2, so they are never prime.And 20 is also divisible by 4 and 5. Its factors are 1, 2, 4, 5, 10, and 20.
What is the numbers is 365 divisible?
365 is divisible by these numbers: 1, 5, 73 and 365.
What prime numbers are divisible by 4?
There aren't any prime numbers divisible by 4. Prime numbers aren't divisible by anything except 1 and the number.
What one digit numbers are divisible by ten?
No one-digit numbers are divisible by 10. 10 is divisible by 1, 2 and 5.
What is equally divisible by 3 and 5 810 or 910?
Clearly, both 810 and 910 are divisible by 5. A wee trick regarding numbers that are a multiple of 3, is that the component numbers, when added together, are divisible by three. So, 654 is divisible by 3, as 6+5+4 = 15 which is divisible by 3. In your example, 810 components add up to 9, which is divisible by 3. But the components of 910 add up to 10 which is not so divisible.
