There are 12 numbers between 100 and 199 that are divisible by eight: 104, 112, 120, 128, 136, 144, 152, 160, 168, 176, 184 and 192.
50
200
No, 199 is not divisible by 9
There are 21 prime numbers between 100 and 199 inclusive. These are as follows: 101 103 107 109 113 127 131 137 139 149 151 157 163 167 173 179 181 191 193 197 199
81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
19 divisible by 5, 14 divisible by 7. Of these, 3 divisible by both.
200
-99
101 to 199 give 50 odd numbers. Their sum is 7,500.[I'm not too certain that the question meant 'the average total'? But, the odd numbers average total would be 7,500 ÷ 50 = 150]
199% = 1.99 = 199/100 = 199/100
101103107109113127131137139149151157163167173179181191193197199
Testing the largest whole number less than 200, 199, we find that it is not evenly divisible by 2, 3, 5, 7, 11 or 13. Since the square root of 199 is between 14 and 15, there's no need to test any prime numbers higher than 14. Therefore, the answer is 198, since it is an even number, and all even numbers are composite numbers because they are divisible by 2. A composite number is the opposite of a prime number.