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What numbers from 1 to 100 are multiples of eleven?

Updated: 8/17/2019
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14y ago

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11, 22, 33, 44, 55, 66, 77, 88 and 99 (11x1 to 9).

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14y ago
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Q: What numbers from 1 to 100 are multiples of eleven?
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How do you write a C program using an integer array to print array numbers up to 100 and then remove all numbers that are divisible by 2 and print out the remaining numbers and continue for 3 to 9?

#include<stdio.h> #include<conio.h> void main() { int i, a[100]; clrscr(); printf("Numbers from 1 to 100"); for(i=1;i<=100;i++) printf(" %d",a[i]); printf("Numbers from 1 to 100 without multiples of 2"); for(i=1;i<=100;i++) { if (a[i]%2 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 3"); for(i=1;i<=100;i++) { if (a[i]%3 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 4"); for(i=1;i<=100;i++) { if (a[i]%4 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 5"); for(i=1;i<=100;i++) { if (a[i]%5 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 6"); for(i=1;i<=100;i++) { if (a[i]%6 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 7"); for(i=1;i<=100;i++) { if (a[i]%7 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 8"); for(i=1;i<=100;i++) { if (a[i]%8 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 9"); for(i=1;i<=100;i++) { if (a[i]%9 !=0) printf(" %d",a[i]); } getch(); }


How many numbers from 1 to 100 are multiples of 1?

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In the numbers 1-100 what percent of the numbers are multiples of 6?

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What fraction of the numbers from 0 to 100 are multiples of 10?

Numbers from 0 to 100 that are multiples of 10 are: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100. That's ten numbers, so the fraction of numbers from 1 to 100 that are multiples of 10 is 10/100. In simplest form it is 1/10.