1,2,3,4,6,12,22,33,44,66,88,99,132
They are: 11 times 12 = 132
66*2=132
113 + 19 = 132 109 + 23 = 132 103 + 29 = 132 101 + 31 = 132 89 + 43 = 132 79 + 53 = 132 73 + 59 = 132 71 + 61 = 132 So there are 8 pairs of prime numbers that sum to 132.
The answer is 11 multiply 12 then you get 132.
1+131=132
Itself and any multiples of 132
11 goes in 12 times. 12 goes in 11 times.
132/9 = 14 2/3
66 X 2=132
How about: 127+5 = 132
33 and 4
66