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What are the two conseccutive numbers which product is 132?
11 & 12 are the integers whose product is 132.
What two prime numbers when multiplied make 132?
132 = 11 x 12 ie 11 x 3 x 2 x 2 . the answer is there are no two prime numbers whose product is 132.
What numbers make the product 132?
1+131=132
What two numbers multipy to make 132?
66 X 2=132
What are the two prime numbers whose sum is 132?
How about: 127+5 = 132
What are the two conseccutive numbers which product is 132?
11 & 12 are the integers whose product is 132.
What two numbers give a sum of 23 and a product of 132?
11 and 12
What two prime numbers when multiplied make 132?
132 = 11 x 12 ie 11 x 3 x 2 x 2 . the answer is there are no two prime numbers whose product is 132.
What numbers make the product 132?
1+131=132
How find 2 numbers with a sum of 23 and product of 132?
as 132 is an even number at least one of the two numbers must also be even 12 + 11 = 23 12 x 11 = 132
What is the least common multiple of 132 and 136?
The LCM of 132 and 136 is 4488. The LCM of a pair is the product of the two numbers divided by their GCF. Since the difference between the two numbers is four, we know that the GCF cannot be larger than four. Four divides evenly into both numbers, so it is the GCF. 132 * 136 / 4 = 4488.
What two numbers have a difference of 1 and a product of 132?
11, 12 -11, -12
What two numbers multipy to make 132?
66 X 2=132
What are the two prime numbers whose sum is 132?
How about: 127+5 = 132
Find 2 consecutive numbers with a product of 132?
11 and 12
What is product of two numbers?
The product of two numbers is the answer to multiplying the two numbers together.
What is the product of two consecutive integers that equals 132?
Let the two consecutive integers be x and x+1. The product of these two integers is x(x+1). Setting this equal to 132 gives us the equation x(x+1) = 132. By expanding the left side of the equation, we get x^2 + x = 132. Rearranging terms, we have x^2 + x - 132 = 0. This is a quadratic equation that can be factored as (x+12)(x-11) = 0. Therefore, the two consecutive integers are 11 and 12, and their product is 132.
