The factor pairs of 15 are (15,1)(5,3)
Neither of them add up to 11.
No integers fulfill your request.
The pair of no. Are 8 & 3 Sum is 8+3=11 Product is =8×3= 24
Homework? 3 and 8.
35
-8 and -3 have a sum of -11 and product of 24
A diamond problem is when there's a number on the top and bottom, the number on the top is the product and the number on the bottom is the sum. You must find two numbers that both have a sum of the number on the top and a product of the number on the bottom. For example, there's a 10 on top and 11 on the bottom, the answer would be 10 and 1, because 10 times 1 equals 10, and 10 plus 1 equals 11. Another example would be, 44 on top and -15 on bottom. The answers would be -11 and -4, because -11 and -4 have a product of 44, and have a sum of -15.
The pair of no. Are 8 & 3 Sum is 8+3=11 Product is =8×3= 24
Homework? 3 and 8.
35
You cannot. There are seven numbers and you cannot pair an odd number of values.
-8 and -3 have a sum of -11 and product of 24
This question doesn't make sense. The sum of 11 and 60 is 71. The product of 11 and 60 is 660.
product means multiplication sum means adding. 6 * 5 = 30 6 + 5 = 11
A diamond problem is when there's a number on the top and bottom, the number on the top is the product and the number on the bottom is the sum. You must find two numbers that both have a sum of the number on the top and a product of the number on the bottom. For example, there's a 10 on top and 11 on the bottom, the answer would be 10 and 1, because 10 times 1 equals 10, and 10 plus 1 equals 11. Another example would be, 44 on top and -15 on bottom. The answers would be -11 and -4, because -11 and -4 have a product of 44, and have a sum of -15.
Let's call the two integer numbers x and y. We know that xy = -26 and x + y = -11. By trying different combinations, we find that the numbers -13 and 2 satisfy both conditions, as -13 multiplied by 2 equals -26 and -13 plus 2 equals -11. So, the integer pair is (-13, 2).
11(5 + 6)
-11 and -1
11 and 11. In general, you can write an equation (or two equations), and solve with the quadratic formula, to solve this type of questions.